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HRID418634

反应详情

EQUATION

反应方程式

HRID 418634 的结构方程式

REACTANTS

反应物

3
结构：O=[N+]([O-])c1ccc(O)c(F)c1
HCID9825

2-Fluoro-4-nitrophenol

C6H4FNO3

结构：CCn1cc(-c2cc3nccc(Cl)c3s2)nc1CN(C)C
HCID58790245

未命名化合物

结构：CCn1cnc(-c2cc3nccc(Oc4ccc([N+](=O)[O-])cc4F)c3s2)c1
HCID66649032

未命名化合物

PRODUCTS

生成物

1
结构：CCn1cc(-c2cc3nccc(Oc4ccc([N+](=O)[O-])cc4F)c3s2)nc1CN(C)C
HCID58790400

未命名化合物

收率 48%

PROCEDURE

实验过程

Starting from the chloride 112 and 2-fluoro-4-nitrophenol and following the same procedure as described above for the synthesis of compound 14 (scheme 4), title compound 113 was obtained as yellow solid in 48% yield. MS (m/z): 442.1 (M+H).