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HRID418652

反应详情

EQUATION

反应方程式

HRID 418652 的结构方程式

REACTANTS

反应物

2
结构：CN(C)Cc1cccc(-c2cc3nccc(Oc4ccc([N+](=O)[O-])cc4F)c3s2)c1
HCID58790281

未命名化合物

结构：Nc1ccc(Oc2ccnc3cc(C(=O)N4CCCC4)sc23)c(F)c1
HCID59424653

未命名化合物

PRODUCTS

生成物

1
结构：CN(C)Cc1cccc(-c2cc3nccc(Oc4ccc(N)cc4F)c3s2)c1
HCID58790102

未命名化合物

收率 44%

PROCEDURE

实验过程

Starting from the compound 149 and following the same procedure as described above for the synthesis of compound 23 (scheme 6), title compound 150 was obtained in 44% yield MS (m/z): 394.0 (M+H).