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HRID418676

反应详情

EQUATION

反应方程式

HRID 418676 的结构方程式

REACTANTS

反应物

2
结构：CN(C)NC(=O)c1cc2nccc(Oc3ccc([N+](=O)[O-])cc3F)c2s1
HCID58790007

未命名化合物

结构：CN(C)N(C)C(=O)c1cc2nccc(Cl)c2s1
HCID58790308

未命名化合物

PRODUCTS

生成物

1
结构：CN(C)N(C)C(=O)c1cc2nccc(Oc3ccc([N+](=O)[O-])cc3F)c2s1
HCID58790384

未命名化合物

收率 66%

PROCEDURE

实验过程

Following the procedure described above for compound 238 (step 2, example 95, scheme 63) but replacing chloride 237 with compound 242, title compound 243 was obtained in 66% yield. MS (m/z): (M+1) 391.1 (100%).