Potassium Iodide → HCID 57586542, compound

HRID 420377Notes

Reaction equation

HRID 420377 reaction equation
[F:1][C:2]1[CH:3]=[C:4]([C:8]2[CH:13]=[C:12]([O:14][CH3:15])[CH:11]=[C:10](N)[CH:9]=2)[CH:5]=[CH:6][CH:7]=1.N([O-])=O.[Na+].[I-:21].[K+]>>[F:1][C:2]1[CH:3]=[C:4]([C:8]2[CH:13]=[C:12]([O:14][CH3:15])[CH:11]=[C:10]([I:21])[CH:9]=2)[CH:5]=[CH:6][CH:7]=1

Participants

4

Reactant 3

HCID 4875Potassium IodideHCID 23668193Sodium NitriteHCID 57586478HCID 57586478, compound

Product 1

HCID 57586542HCID 57586542, compoundYield 78%

Procedure

A similar procedure as described in Example 12, step 5 was used, starting from 3′-fluoro-5-methoxy-biphenyl-3-ylamine (940 mg, 4.32 mmol), sodium nitrite (545 mg, 7.79 mmol), and potassium iodide (1.44 mg, 8.65 mmol) to afford 3′-fluoro-3-iodo-5-methoxy-biphenyl (1.1 g, 78%) as an amorphous light yellow oil: ES(+)-HRMS m/e calculated for C13H10FIO (M+H)+ 329.1190, found 329.1192.

Sources & evidence

ORD record
ord-4047dbda1ba4442aa969b21db34e97ff
Source dataset
uspto-grants-2012_01
Patent number
US08093385B2

Reaction notes

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