Potassium Iodide → HCID 57586542, compound

Participants

Reaction Steps

A similar procedure as described in Example 12, step 5 was used, starting from 3′-fluoro-5-methoxy-biphenyl-3-ylamine (940 mg, 4.32 mmol), sodium nitrite (545 mg, 7.79 mmol), and potassium iodide (1.44 mg, 8.65 mmol) to afford 3′-fluoro-3-iodo-5-methoxy-biphenyl (1.1 g, 78%) as an amorphous light yellow oil: ES(+)-HRMS m/e calculated for C13H10FIO (M+H)+ 329.1190, found 329.1192.

Provenance & Evidence