Sodium Hydroxide → HCID 66657660, compound
Reaction equation
[CH2:1]([O:3][C:4]([C:6]1[C:14]2[C:9](=[CH:10][CH:11]=[C:12]([O:15][C:16]3[CH:21]=[CH:20][C:19]([O:22][C:23]([F:26])([F:25])[F:24])=[CH:18][CH:17]=3)[CH:13]=2)[N:8]([C:27]2[CH:32]=[CH:31][C:30]([N:33]([CH2:36][CH3:37])[CH2:34][CH3:35])=[CH:29][CH:28]=2)[C:7]=1[CH2:38][C:39]([O:41]CC)=[O:40])=[O:5])[CH3:2].[OH-].[Na+]>O1CCOCC1>[CH2:1]([O:3][C:4]([C:6]1[C:14]2[C:9](=[CH:10][CH:11]=[C:12]([O:15][C:16]3[CH:17]=[CH:18][C:19]([O:22][C:23]([F:26])([F:24])[F:25])=[CH:20][CH:21]=3)[CH:13]=2)[N:8]([C:27]2[CH:28]=[CH:29][C:30]([N:33]([CH2:36][CH3:37])[CH2:34][CH3:35])=[CH:31][CH:32]=2)[C:7]=1[CH2:38][C:39]([OH:41])=[O:40])=[O:5])[CH3:2]Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
1-(4-Diethylaminophenyl)-2-ethoxycarbonylmethyl-5-(4-trifluoromethoxyphenoxy)indole-3-carboxylic acid ethyl ester (150 mg, 0.25 mmol, see step (a) Example 75) was hydrolysed at 55° C. for 3 h with NaOH (aq, 2 M, 2 mL) and dioxane (2 mL). Work-up as described in step (d) Example 1 gave the title compound. Yield 110 mg (77%).
Sources & evidence
- ORD record
- ord-a99ff54029384bcb8504159f18e75d74
- Source dataset
- uspto-grants-2012_01
- Patent number
- US08097623B2
Reaction notes
Loading…