Sodium Iodide → HCID 54358058, compound
Reaction equation
[CH2:1]1[O:9][C:8]2[CH:7]=[CH:6][C:5]([CH2:10][CH2:11][CH:12]=[CH:13][CH2:14][CH2:15]Br)=[CH:4][C:3]=2[O:2]1.[I-:17].[Na+]>CC(C)=O>[CH2:1]1[O:9][C:8]2[CH:7]=[CH:6][C:5]([CH2:10][CH2:11][CH:12]=[CH:13][CH2:14][CH2:15][I:17])=[CH:4][C:3]=2[O:2]1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
6-(3,4-Methylenedioxyphenyl)-3-hexenyl iodide [VI; Ar is 3,4-methylenedioxyphenyl, R is H] was prepared from 12.9 g. of 6-(3,4-methylenedioxyphenyl)-3-hexenyl bromide (Preparation C2) and 7 g. of sodium iodide in 120 ml. of acetone, refluxed for three hours, affording 12.5 g. of product as an oil.
Workup
- customaffording 12.5 g
Sources & evidence
- ORD record
- ord-c0f079a9aa654a26a8918258dd14b75d
- Source dataset
- uspto-grants-1979_10
- Patent number
- US04171378
Reaction notes
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