Sodium Iodide → HCID 54358058, compound

HRID 426868Notes

Reaction equation

HRID 426868 reaction equation
[CH2:1]1[O:9][C:8]2[CH:7]=[CH:6][C:5]([CH2:10][CH2:11][CH:12]=[CH:13][CH2:14][CH2:15]Br)=[CH:4][C:3]=2[O:2]1.[I-:17].[Na+]>CC(C)=O>[CH2:1]1[O:9][C:8]2[CH:7]=[CH:6][C:5]([CH2:10][CH2:11][CH:12]=[CH:13][CH2:14][CH2:15][I:17])=[CH:4][C:3]=2[O:2]1

Participants

4

Procedure

6-(3,4-Methylenedioxyphenyl)-3-hexenyl iodide [VI; Ar is 3,4-methylenedioxyphenyl, R is H] was prepared from 12.9 g. of 6-(3,4-methylenedioxyphenyl)-3-hexenyl bromide (Preparation C2) and 7 g. of sodium iodide in 120 ml. of acetone, refluxed for three hours, affording 12.5 g. of product as an oil.

Workup

  1. customaffording 12.5 g

Sources & evidence

ORD record
ord-c0f079a9aa654a26a8918258dd14b75d
Source dataset
uspto-grants-1979_10
Patent number
US04171378

Reaction notes

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