Sodium Iodide → HCID 14977896, compound

HRID 426871Notes

Reaction equation

HRID 426871 reaction equation
[CH3:1][O:2][C:3]1[CH:8]=[CH:7][C:6]([CH2:9][CH2:10][CH2:11][CH2:12][CH2:13][CH2:14]Br)=[CH:5][CH:4]=1.[I-:16].[Na+]>CC(=O)CC>[CH3:1][O:2][C:3]1[CH:8]=[CH:7][C:6]([CH2:9][CH2:10][CH2:11][CH2:12][CH2:13][CH2:14][I:16])=[CH:5][CH:4]=1

Participants

4

Reactant 2

HCID 5238Sodium IodideHCID 10588171Benzene, 1-(6-bromohexyl)-4-methoxy-

Product 1

HCID 14977896HCID 14977896, compound

Reagents, catalysts & solvents 1

HCID 6569Methyl Ethyl KetoneSolvent

Procedure

6-(4-Methoxyphenyl)hexyl iodide [VIa; Ar is 4-CH3OC6H4, R is H] was prepared from 16.3 g. of 6-(4-methoxyphenyl)hexyl bromide (Preparation C11) and 9.93 g. of sodium iodide in 325 ml. of 2-butanone, to give 19.3 g. of product as a pale yellow oil.

Sources & evidence

ORD record
ord-43567d7cb1f8456dab5ab0756a578554
Source dataset
uspto-grants-1979_10
Patent number
US04171378

Reaction notes

Loading…