Water → HCID 12232363, compound

HRID 435635Notes

Reaction equation

HRID 435635 reaction equation
[Br:1][C:2]1[CH:17]=[CH:16][C:5]2[S:6][C:7]3[CH:15]=[CH:14][CH:13]=[CH:12][C:8]=3[C:9](=[O:11])[CH2:10][C:4]=2[CH:3]=1.[BH4-].[Na+].O>C(O)C>[Br:1][C:2]1[CH:17]=[CH:16][C:5]2[S:6][C:7]3[CH:15]=[CH:14][CH:13]=[CH:12][C:8]=3[CH:9]([OH:11])[CH2:10][C:4]=2[CH:3]=1

Participants

5

Reactant 3

HCID 962WaterHCID 4311764Sodium borohydrideHCID 12232358HCID 12232358, compound

Product 1

HCID 12232363HCID 12232363, compound

Reagents, catalysts & solvents 1

HCID 702EthanolSolvent

Procedure

50 g of 2-bromo- 10,11-dihydro-dibenzo[b,f]thiepin-10-one are dispersed in 250 ml of ethanol, treated with 9.9 g of sodium borohydride and stirred for 1 hour. After the addition of water, the mixture is extracted with ether. The organic phase is washed with water, dried over magnesium sulphate and evaporated. There is obtained 2-bromo- 10,11-dihydro-dibenzo-[b,f]thiepin-10-ol of melting point 108°-110° C.

Workup

  1. extractionthe mixture is extracted with ether
  2. washThe organic phase is washed with water
  3. dry with materialdried over magnesium sulphate
  4. customevaporated

Sources & evidence

ORD record
ord-a009f61a41b84c809b6293bf5b113633
Source dataset
uspto-grants-1977_02
Patent number
US04006145

Reaction notes

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