反应详情

19.4 g Di-sodium tetra-iodoterephthalate (0.0272 mole) and 0.5 g sodium iodide were stirred in 35 ml 3-chloro-1,2-propanediol for 20 hours at 100° C, the reaction mixture was worked up as in Example 1, and the bis-2,3-dihydroxypropyl ester of tetra-iodoterephthalic acid was obtained in an amount of 18.9 g (85% yield). When recrystallized from ethanol, it melted at 230° C (decomp.), gave an Rf value of 0.60, and was identified by elementary analysis: