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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 442053Generated: October 25, 2026

Sodium Iodide → 2,3,5,6-Tetraiodo-1,4-benzenedicarboxylic acid

https://huagongshe.com/reaction/442053

Reaction equation

Participants

RoleNameHCIDCharge
ReactantSodium IodideHCID 5238—
ReactantPropylene ChlorohydrinHCID 6566—
ReactantDi-sodium tetra-iodoterephthalateHCID 86735015—
SolventDimethylformamideHCID 6228—
Product2,3,5,6-Tetraiodo-1,4-benzenedicarboxylic acidHCID 1899387560%

Reaction Steps

21.4 g Di-sodium tetra-iodoterephthalate, 0.5 g sodium iodide, and 10 g 2-chloropropanol were heated with stirring in 150 ml dimethylformamide at 100° C for 10 hours. The solvent was distilled off, and the residue was suspended in water and purified as described in Example 1. 14.15 g Bis-1-hydroxy-2-propyl ester of tetra-iodoterephthalic acid (60% yield) was recovered. It melted and decomposed at about 225° C.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS04044048
Source datasetuspto-grants-1977_08
ORD IDord-4095f8a52fe14af19effe7087d3afaea
Source noteuspto-grants-1977_08