Sodium Iodide → 2,3,5,6-Tetraiodo-1,4-benzenedicarboxylic acid
Reaction equation
[I:1][C:2]1[C:7]([C:8]([O-:10])=[O:9])=[C:6]([I:11])[C:5]([I:12])=[C:4]([C:13]([O-:15])=[O:14])[C:3]=1[I:16].[Na+].[Na+].[I-].[Na+].ClC(C)CO>CN(C)C=O>[I:1][C:2]1[C:7]([C:8]([OH:10])=[O:9])=[C:6]([I:11])[C:5]([I:12])=[C:4]([C:13]([OH:15])=[O:14])[C:3]=1[I:16]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
21.4 g Di-sodium tetra-iodoterephthalate, 0.5 g sodium iodide, and 10 g 2-chloropropanol were heated with stirring in 150 ml dimethylformamide at 100° C for 10 hours. The solvent was distilled off, and the residue was suspended in water and purified as described in Example 1. 14.15 g Bis-1-hydroxy-2-propyl ester of tetra-iodoterephthalic acid (60% yield) was recovered. It melted and decomposed at about 225° C.
Workup
- distillationThe solvent was distilled off
- custompurified
Sources & evidence
- ORD record
- ord-4095f8a52fe14af19effe7087d3afaea
- Source dataset
- uspto-grants-1977_08
- Patent number
- US04044048
Reaction notes
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