1-Fluoro-2-methoxy-4-nitrobenzene → 4-Fluoro-3-methoxyaniline
Reaction equation
[F:1][C:2]1[CH:7]=[CH:6][C:5]([N+:8]([O-])=O)=[CH:4][C:3]=1[O:11][CH3:12].[H][H]>[Pd].O1CCOCC1>[F:1][C:2]1[CH:7]=[CH:6][C:5]([NH2:8])=[CH:4][C:3]=1[O:11][CH3:12]Participants
5
Reactant 2
Product 1
Reagents, catalysts & solvents 2
Procedure
A suspension of 10 grams of 2-fluoro-5-nitroanisole and 100 ml. of dioxane is reduced catalytically under 40 p.s.i. of hydrogen and 1.0 gram of 5% Pd/C. After the uptake of hydrogen ceases, the catalyst is filtered, and the filtrate is concentrated in vacuo to yield 4-fluoro-3-methoxyaniline.
Workup
- filtrationAfter the uptake of hydrogen ceases, the catalyst is filtered
- concentrationthe filtrate is concentrated in vacuo
Sources & evidence
- ORD record
- ord-9ac8f6ce11bc48d6b36b1c2544316579
- Source dataset
- uspto-grants-1977_08
- Patent number
- US04044049
Reaction notes
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