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HRID443482

反应详情

EQUATION

反应方程式

HRID 443482 的结构方程式

REACTANTS

反应物

4
结构：Cl
HCID313

Hydrochloric Acid

ClH

结构：C=O
HCID712

Formaldehyde

CH2O

结构：OP(O)O
HCID107909

Phosphorous acid

H3O3P

结构：Cl.ClCCNC1CCCCC1
HCID13756691

未命名化合物

PRODUCTS

生成物

1
结构：O=P(O)(O)CN(CCCl)C1CCCCC1
HCID20564015

未命名化合物

AUXILIARIES

试剂、催化剂与溶剂

1
结构：O
溶剂HCID962

Water

H2O

PROCEDURE

实验过程

A total of 101 parts of N-(2-chloroethyl)cyclohexylamine hydrochloride, 41.5 parts phosphorous acid in 101 parts water, 75 parts of 37% aqueous hydrochloric acid, and 104 parts of 37% aqueous formaldehyde were used to prepare Reagent E-2.

WORKUP

后处理

  1. customto prepare Reagent E-2