HRID454104

反应详情

EQUATION

反应方程式

HRID 454104 的结构方程式

PROCEDURE

实验过程

Using an analogous procedure to that described for Example 121, 4-chloro-6-methoxy-7-(3-morpholinopropoxy)quinazoline (160 mg, 0.47 mol), (prepared as described for the starting material in Example 1), was reacted with 6-hydroxy-2-methylindole (84 mg, 0.57 mol), (Eur. J. Med. Chem. 1975, 10, 187), to give 6-methoxy-4-(2-methylindol-6-yloxy)-7-(3-morpholinopropoxy)quinazoline (157 mg, 73%).

WORKUP

后处理

  1. custom(prepared