Ammonia → HCID 54544392, compound

Participants

Reaction Steps

10 m mol of 2-octadecyleicosanyl-p-dimethoxybenzene was treated with sodium in liquid ammonia, thus forming 7.2 m mol of 2-octadecyl-eicosanyl-cyclohexane-1,4-dione. This product, 6 m mol, was reacted with 13 m mol of malononitrile. The resultant reaction product was treated with bromine in pridine, thus obtaining 7 m mol of 2-octadecyleicosanyl-tetracyanoquinodimethane, which is represented by the following formula: ##STR47##

Provenance & Evidence