Hydrogen Bromide → 4-Hydroxy-6-fluorophenanthridine

HRID 482155Notes

Reaction equation

HRID 482155 reaction equation
C[O:2][C:3]1[C:16]2[C:7](=[C:8]3[C:13](=[C:14]([F:17])[N:15]=2)[CH:12]=[CH:11][CH:10]=[CH:9]3)[CH:6]=[CH:5][CH:4]=1.Br.C(=O)([O-])[O-].[Na+].[Na+]>>[OH:2][C:3]1[C:16]2[C:7](=[C:8]3[C:13](=[C:14]([F:17])[N:15]=2)[CH:12]=[CH:11][CH:10]=[CH:9]3)[CH:6]=[CH:5][CH:4]=1

Participants

4

Procedure

A mixed solution comprising 115 mg of 4-methoxy-6-fluorophenanthridine and 5 ml of 48% hydrobromic acid was allowed to react at 116° C. for a period of 14 hr. After the completion of the reaction, the reacted solution was introduced into an aqueous solution of sodium carbonate and the product was extracted by ethyl acetate. After ethyl acetate was distilled away, the residue was purified by column chromatography to obtain 104.5 mg of 4-hydroxy-6-fluorophenanthridine on recrystallization from hexane (yield 96.9%).

Workup

  1. customto react at 116° C. for a period of 14 hr
  2. customAfter the completion of the reaction
  3. extractionthe product was extracted by ethyl acetate
  4. distillationAfter ethyl acetate was distilled away
  5. customthe residue was purified by column chromatography

Sources & evidence

ORD record
ord-af6e26c9a12e43c29a91459a2c6c6148
Source dataset
uspto-grants-1998_08
Patent number
US05792863

Reaction notes

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