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HRID485024

反应详情

EQUATION

反应方程式

HRID 485024 的结构方程式

REACTANTS

反应物

3
结构：CCOC(=O)CBr
HCID7748

Ethyl bromoacetate

C4H7BrO2

结构：[H-].[Na+]
HCID24758

Sodium hydride

HNa

结构：CC(C)CC(=O)CNC(=O)c1ccc(Cl)cc1
HCID13490307

4-Chloro-N-(4-methyl-2-oxopentyl)benzamide

C13H16ClNO2

PRODUCTS

生成物

1
结构：CCOC(=O)CC(NC(=O)c1ccc(Cl)cc1)C(=O)CC(C)C
HCID13488803

未命名化合物

收率 74.7%

PROCEDURE

实验过程

2.5 g of N-(4-chlorobenzoyl)isovalerylmethylamine, 0.5 g of 61% sodium hydride and 1.81 g of ethyl bromoacetate are treated in the same manner as described in Preparation 1-(5). 2.5 g of ethyl 3-(4-chlorobenzoylamino)-3-isovalerylpropionate are thereby obtained. Yield: 74.4%.

WORKUP

后处理

  1. customas described in Preparation 1-(5)