Hydrochloric Acid → HCID 19095679, compound
Reaction equation
[C:1]([C:5]1[CH:10]=[CH:9][C:8]([S:11]([NH:14][C:15]2[C:20]([O:21][C:22]3[CH:27]=[C:26]([O:28][CH3:29])[CH:25]=[CH:24][C:23]=3[Cl:30])=[C:19]([O:31][CH2:32][CH2:33][S:34][CH3:35])[N:18]=[C:17]([CH2:36][CH3:37])[N:16]=2)(=[O:13])=[O:12])=[CH:7][CH:6]=1)([CH3:4])([CH3:3])[CH3:2].Cl.C[OH:40]>[OH-].[Na+].O>[C:1]([C:5]1[CH:6]=[CH:7][C:8]([S:11]([NH:14][C:15]2[C:20]([O:21][C:22]3[CH:27]=[C:26]([O:28][CH3:29])[CH:25]=[CH:24][C:23]=3[Cl:30])=[C:19]([O:31][CH2:32][CH2:33][S:34]([CH3:35])=[O:40])[N:18]=[C:17]([CH2:36][CH3:37])[N:16]=2)(=[O:12])=[O:13])=[CH:9][CH:10]=1)([CH3:4])([CH3:3])[CH3:2]Participants
Reactant 3
Product 1
Reagents, catalysts & solvents 2
Procedure
210 mg of 4-tert-butyl-N-[5-(2-chloro-5-methoxyphenoxy)-2-ethyl-6-(2-methylsulphanyl-ethoxy)-pyrimidin-4-yl]-benzenesulfonamide were dissolved in 5 ml of MeOH and 0.2 ml of 1N NaOH. 95 mg of NalO4 dissolved in 0.5 ml of H2O were added thereto and the mixture was stirred at room temperature for 5 hours, whereby a suspension resulted. Then, 0.2 ml of 1N HCl was added and the mixture was subsequently evaporated to dryness. The residue was partitioned between ethyl acetate and 0.1N HCl and worked-up as usual. For purification, the compound was chromatographed on silica gel using ethyl acetate-MeOH (6:1 by vol.) as the eluent. There were obtained 160 mg of (RS)-4-tert-butyl-N-[5-(2-chloro-5-methoxy-phenoxy)-2-ethyl-6-(2-methylsulphinyl-ethoxy)pyrimidin-4-yl]-benzenesulfonamide as a white powder. MS: 581 (M).
Workup
- additionwere added
- customwhereby a suspension resulted
- customthe mixture was subsequently evaporated to dryness
- customThe residue was partitioned between ethyl acetate and 0.1N HCl
- customFor purification
- customthe compound was chromatographed on silica gel
Sources & evidence
- ORD record
- ord-b0faa072379f450fbdba277095f04a33
- Source dataset
- uspto-grants-1994_03
- Patent number
- US05292740
Reaction notes
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