HRID500057

反应详情

EQUATION

反应方程式

HRID 500057 的结构方程式

PROCEDURE

实验过程

The title compound was prepared by method of Example 4, substituting 43 g (0.181 mol) of 1,1,1-trifluoro-2-trifluoromethyl-4-methyl-2,5-pentanediol (2) for 1,1,1-trifluoro-2-trifluoromethyl-2,5-pentanediol (4) and 226 mL (0.362 mol) of methyllithium (1.6M in ether) in lieu of the n-butyllithium, and using 20.7 g (0.199 mol) of methacryloyl chloride, to yield 35 g (76%) of the title compound as a clear colorless oil.

WORKUP

后处理

  1. customThe title compound was prepared by method of Example 4