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HRID500842

反应详情

EQUATION

反应方程式

HRID 500842 的结构方程式

REACTANTS

反应物

3
结构：O=[N+]([O-])c1ccc(O)cc1
HCID980

4-Nitrophenol

C6H5NO3

结构：Clc1ccnc2cc(Br)sc12
HCID18382774

2-Bromo-7-chlorothieno[3,2-b]pyridine

C7H3BrClNS

结构：O=[N+]([O-])c1ccc(Oc2ccnc3cc(Br)sc23)c(F)c1
HCID59424521

未命名化合物

PRODUCTS

生成物

1
结构：O=[N+]([O-])c1ccc(Oc2ccnc3cc(Br)sc23)cc1
HCID59424461

未命名化合物

收率 48%

PROCEDURE

实验过程

Starting from the compound 41 (scheme 8) and following the procedure described above for the synthesis of compound 42 (scheme 8) but replacing 2-fluoro-4-nitrophenol for 4-nitrophenol, title compound 197 was obtained in 48% yield. LRMS (M+1) 350.9 (100%). 352.9 (100%).