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HRID500850

反应详情

EQUATION

反应方程式

HRID 500850 的结构方程式

REACTANTS

反应物

3
结构：O=[N+]([O-])c1ccc(O)cc1
HCID980

4-Nitrophenol

C6H5NO3

结构：Clc1ccnc2ccsc12
HCID11275251

7-Chlorothieno[3,2-b]pyridine

C7H4ClNS

结构：CN(C)C(=O)c1cc2nccc(Oc3ccc([N+](=O)[O-])cc3F)c2s1
HCID59424475

未命名化合物

PRODUCTS

生成物

1
结构：O=[N+]([O-])c1ccc(Oc2ccnc3ccsc23)cc1
HCID59424636

未命名化合物

收率 89%

PROCEDURE

实验过程

Staring from the chloride 2, following the procedure described above for the synthesis of compound 6 (scheme 1, example 1) but substituting 2-fluoro-4-nitrophenol for 4-nitrophenol, title compound 212 was obtained in 89% yield. MS (m/z) 273.0 (M+H).