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HRID501254

反应详情

EQUATION

反应方程式

HRID 501254 的结构方程式

REACTANTS

反应物

2
结构：Cl
HCID313

Hydrochloric Acid

ClH

结构：Cc1cc(N2CC(c3ccc(F)cc3)CS2(=O)=O)c(S(C)(=O)=O)cc1C(=O)NC(=N)N
HCID178427991

未命名化合物

PRODUCTS

生成物

1
结构：Cc1cc(N2CC(c3ccc(F)cc3)CS2(=O)=O)c(S(C)(=O)=O)cc1C(=O)NC(=N)N.Cl
HCID178427992

未命名化合物

PROCEDURE

实验过程

84 mg of N-{4-[4-(4-fluorophenyl)-1,1-dioxoisothiazolidin-2-yl]-5-methanesulfonyl-2-methylbenzoyl}guanidine enantiomer A were converted into the hydrochloride in analogy to Example 7h), and 90 mg of white crystals were obtained.

WORKUP

后处理

  1. customwere obtained