HRID50188

反应详情

EQUATION

反应方程式

HRID 50188 的结构方程式

PROCEDURE

实验过程

Following the same procedure as that described in Example 1E, 6-bromo-4-(3-chloro-phenyl)-2-methoxy-quinoline (0.200 g, 0.574 mmol) and (6-methyl-pyridin-3-yl)-(3-methyl-3H-imidazol-4-yl)-methanone (0.105 g, 0.522 mmol) generated 0.118 g (48% yield) of [4-(3-chloro-phenyl)-2-methoxy-quinolin-6-yl]-(6-methyl-pyridin-3-yl)-(3-methyl-3H-imidazol-4-yl)-methanol.