HRID506809

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID2776493

4-(4-Methylpiperazino)benzylamine

C12H19N3

结构：COc1cc2c(nc1OC)c(-c1cc3c(C=O)ccnc3n1S(=O)(=O)c1ccc(C)cc1)cn2C

HCID86618635

未命名化合物

PRODUCTS

生成物

结构：COc1cc2c(nc1OC)c(-c1cc3c(CNCc4ccc(N5CCN(C)CC5)cc4)ccnc3n1S(=O)(=O)c1ccc(C)cc1)cn2C

HCID68469454

未命名化合物

PROCEDURE

实验过程

The product is prepared by following the procedure described in example 34, stage (j), starting with 0.1 g of 2-(5,6-dimethoxy-1-methyl-1H-pyrrolo[3,2-b]pyridin-3-yl)-1-(toluene-4-sulfonyl)-1H-pyrrolo[2,3-b]pyridin-4-carbaldehyde and 0.209 cm3 of 4-(4-methylpiperazino)benzylamine instead of the cyclopropylamine used in example 34, stage (j). After purification by flash-pack chromatography (SiO2, dichloromethane/methanol 90/10 by volume as eluents), 0.083 g of [2-(5,6-dimethoxy-1-methyl-1H-pyrrolo[3,2-b]pyridin-3-yl)-1-(toluene-4-sulfonyl)-1H-pyrrolo[2,3-b]pyridin-4-ylmethyl]-[4-(4-methylpiperazin-1-yl)-benzyl]amine is obtained with the following characteristics:

WORKUP

后处理

customThe product is prepared
customAfter purification by flash-pack chromatography (SiO2, dichloromethane/methanol 90/10 by volume as eluents)

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-402e3a882823474ca9f29e8bdf507cac
来源数据集: uspto-grants-2010_08
DOI: 10.6084/m9.figshare.5104873.v1
专利: US07786114B2
来源说明: uspto-grants-2010_08

反应 SMILES

[CH3:1][O:2][C:3]1[N:8]=[C:7]2[C:9]([C:13]3[N:23]([S:24]([C:27]4[CH:32]=[CH:31][C:30]([CH3:33])=[CH:29][CH:28]=4)(=[O:26])=[O:25])[C:16]4[N:17]=[CH:18][CH:19]=[C:20]([CH:21]=O)[C:15]=4[CH:14]=3)=[CH:10][N:11]([CH3:12])[C:6]2=[CH:5][C:4]=1[O:34][CH3:35].[CH3:36][N:37]1[CH2:42][CH2:41][N:40]([C:43]2[CH:50]=[CH:49][C:46]([CH2:47][NH2:48])=[CH:45][CH:44]=2)[CH2:39][CH2:38]1>>[CH3:1][O:2][C:3]1[N:8]=[C:7]2[C:9]([C:13]3[N:23]([S:24]([C:27]4[CH:32]=[CH:31][C:30]([CH3:33])=[CH:29][CH:28]=4)(=[O:26])=[O:25])[C:16]4=[N:17][CH:18]=[CH:19][C:20]([CH2:21][NH:48][CH2:47][C:46]5[CH:45]=[CH:44][C:43]([N:40]6[CH2:39][CH2:38][N:37]([CH3:36])[CH2:42][CH2:41]6)=[CH:50][CH:49]=5)=[C:15]4[CH:14]=3)=[CH:10][N:11]([CH3:12])[C:6]2=[CH:5][C:4]=1[O:34][CH3:35]