Lithium Hydroxide → HCID 86624092, compound
Reaction equation
[Cl:1][C:2]1[CH:3]=[C:4]([C:19]([O:21]C)=[O:20])[C:5](=[O:18])[NH:6][C:7]=1[C:8]([F:17])([F:16])[C:9]([F:15])([F:14])[C:10]([F:13])([F:12])[F:11].[OH-].[Li+]>CO.O>[Cl:1][C:2]1[CH:3]=[C:4]([C:19]([OH:21])=[O:20])[C:5](=[O:18])[NH:6][C:7]=1[C:8]([F:16])([F:17])[C:9]([F:15])([F:14])[C:10]([F:12])([F:13])[F:11]Participants
5
Reactant 2
Product 1
Reagents, catalysts & solvents 2
Procedure
1.54 g (4.33 mmol) of methyl 5-chloro-6-(heptafluoropropyl)-2-oxo-1,2-dihydropyridine-3-carboxylate were dissolved in 23 ml of methanol, and a solution of 0.16 g (6.5 mmol) of lithium hydroxide in 13 ml of water was added. After two hours of heating under reflux, the methanol was distilled off, and the aqueous solution that remained was washed with dichloromethane. The aqueous phase was then acidified with 2N hydrochloric acid and extracted with dichloromethane. Drying and concentration of the extract gave 1.45 g (98% o of theory) of a brownish powder.
Workup
- temperatureAfter two hours of heating
- temperatureunder reflux
- distillationthe methanol was distilled off
- washthe aqueous solution that remained was washed with dichloromethane
- extractionextracted with dichloromethane
- customDrying
- customconcentration of the extract gave 1.45 g (98% o of theory) of a brownish powder
Sources & evidence
- ORD record
- ord-8a54dbf02f274956a1df08b7c04caffa
- Source dataset
- uspto-grants-2015_08
- Patent number
- US09102623B2
Reaction notes
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