Sodium Hydroxide → HCID 89501036, compound
Reaction equation
[Cl:1][C:2]1[C:3]([F:19])=[CH:4][C:5]([N:14]2[CH:18]=[N:17][N:16]=[N:15]2)=[C:6](/[CH:8]=[CH:9]/[C:10]([O:12]C)=[O:11])[CH:7]=1.[OH-].[Na+]>CO.C1COCC1>[Cl:1][C:2]1[C:3]([F:19])=[CH:4][C:5]([N:14]2[CH:18]=[N:17][N:16]=[N:15]2)=[C:6](/[CH:8]=[CH:9]/[C:10]([OH:12])=[O:11])[CH:7]=1Participants
5
Reactant 2
Product 1
Reagents, catalysts & solvents 2
Procedure
To Intermediate 5C (5 g, 17.7 mmol) in MeOH (50 mL) and THF (25 mL) was added 10% NaOH solution (25 mL). After 2 h, the reaction was concentrated and the residue was diluted with H2O. The pH was adjusted to 2 to 3 with 1.5 N HCl and the resultant solid was filtered and washed with petroleum ether to afford 2 g of Intermediate 5. MS (ESI) m/z: 269.0 (M+H)+.
Workup
- concentrationthe reaction was concentrated
- additionthe residue was diluted with H2O
- filtrationthe resultant solid was filtered
- washwashed with petroleum ether
Sources & evidence
- ORD record
- ord-08fe8b1240d14b43aab1cac9d3112350
- Source dataset
- uspto-grants-2015_08
- Patent number
- US09108951B2
Reaction notes
Loading…