Potassium Carbonate → HCID 59915831, compound
Reaction equation
C([O-])([O-])=O.[K+].[K+].[O:7]=[C:8]1[C@@H:14]([N:15](C)[C:16](=O)C(F)(F)F)[CH2:13][CH2:12][S:11][C@H:10]2[CH2:23][CH2:24][CH2:25][C@@H:26]([C:27]([O:29][CH3:30])=[O:28])[N:9]12>O.CO>[CH3:16][NH:15][C@H:14]1[CH2:13][CH2:12][S:11][C@H:10]2[CH2:23][CH2:24][CH2:25][C@@H:26]([C:27]([O:29][CH3:30])=[O:28])[N:9]2[C:8]1=[O:7]Participants
Reactant 2
Product 1
Reagents, catalysts & solvents 2
Procedure
A solution of K2CO3 (18.8 mg, 0.136 mmol) in water (0.16 mL) was added to a solution of (4S,7S,10aS)-methyl 5-oxo-4-(2,2,2-trifluoro-N-methylacetamido)octahydro-2H-pyrido[2,1-b][1,3]thiazepine-7-carboxylate (45.6 mg, 0.124 mmol) in MeOH (0.4 mL). The reaction mixture was stirred at rt for 2 hr. After a total of 3 hr, a stream of nitrogen gas was used to partially evaporate the MeOH. The residue was then partitioned between CHCl3 and saturated aqueous NaCl. The aqueous layer was isolated and extracted once again with CHCl3. All organic phases were combined, dried over MgSO4 and concentrated to give (4S,7S,10aS)-methyl 4-(methylamino)-5-oxooctahydro-2H-pyrido[2,1-b][1,3]thiazepine-7-carboxylate (34 mg, 0.12 mmol, 100% yield) of a yellow oil. Anal. Calcd. for C12H20N2O3S m/z 272.3. found: 273.2 (M+H)+.
Workup
- customAfter a total of 3 hr
- customto partially evaporate the MeOH
- customThe residue was then partitioned between CHCl3 and saturated aqueous NaCl
- customThe aqueous layer was isolated
- extractionextracted once again with CHCl3
- dry with materialdried over MgSO4
- concentrationconcentrated
Sources & evidence
- ORD record
- ord-f966e61a4d564714a4d4a961e48eec9d
- Source dataset
- uspto-grants-2016_05
- Patent number
- US09346852B2
Reaction notes
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