HRID536544

反应详情

EQUATION

反应方程式

HRID 536544 的结构方程式

PROCEDURE

实验过程

In the same way as for the compound from Example 24A, 267 mg (0.87 mmol) of the compound from Example 19A were reacted with 199 mg (0.87 mmol) of methyl 3-(bromomethyl)benzoate. This gave 302 mg (76% of theory) of the target compound.