HRID55006
反应详情
EQUATION
反应方程式
REACTANTS
反应物
PRODUCTS
生成物
PROCEDURE
实验过程
The procedure similar to that described in Example 1 was repeated, except that 300 mg (0.63 mmol) of Compound 24 was used and ethyl iodide was used in place of methyl iodide. As a result, 213.1 mg (yield: 67%) of Compound 2 was obtained as pale yellow crystals.