HRID55007
反应详情
EQUATION
反应方程式
REACTANTS
反应物
PRODUCTS
生成物
PROCEDURE
实验过程
The procedure similar to that described in Example 1 was repeated, except that 300 mg (0.63 mmol) of Compound 24 was used and propyl iodide was used in place of methyl iodide. As a result, 209.9 mg (yield: 64%) of Compound 3 was obtained as pale yellow crystals.