HRID55012

反应详情

EQUATION

反应方程式

HRID 55012 的结构方程式

PROCEDURE

实验过程

The procedure similar to that described in Example 1 was repeated, except that 200 mg (0.42 mmol) of Compound 24 was used and benzyl bromide was used in place of methyl iodide. As a result, 190.5 mg (yield: 80%) of Compound 8 was obtained as pale yellow crystals.