HRID55023

反应详情

EQUATION

反应方程式

HRID 55023 的结构方程式

PROCEDURE

实验过程

The procedure similar to that described in Example 1 was repeated, except that 300 mg (0.64 mmol) of Compound h was used in place of Compound 24 and propyl iodide was used in place of methyl iodide. As a result, 200.9 mg (yield: of Compound 42 was obtained as white crystals.