HRID55048

反应详情

EQUATION

反应方程式

HRID 55048 的结构方程式

PROCEDURE

实验过程

The procedure similar to that described in Example 1 was repeated, except that 100.0 mg (0.22 mmol) of Compound 90 obtained in Example 80 was used in place of Compound 24 and propyl iodide was used in place of methyl iodide. As a result, 69.0 mg (yield: 64%) of Compound 92 was obtained as white crystals.