Ethyl bromoacetate → HCID 22923401, compound

Participants

Reaction Steps

The procedure similar to that described in Example 1 was repeated, except that 500.0 mg (1.12 mmol) of Compound 90 obtained in Example 80 was used in place of Compound 24 and ethyl bromoacetate was used in place of methyl iodide. As a result, 323.3 mg (yield: 54%) of Compound 94 was obtained as white crystals.

Provenance & Evidence