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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 558972Generated: October 30, 2026

Sodium Iodide → 5-Fluoro-1-(2-methoxyethyl)-3,4-dihydro-1H-quinoxalin-2-one

https://huagongshe.com/reaction/558972

Reaction equation

Participants

RoleNameHCIDCharge
ReactantSodium IodideHCID 5238—
ReactantSodium hydrideHCID 24758—
Reactant2-Bromoethyl methyl etherHCID 80972—
Reactant5-Fluoro-1,2,3,4-tetrahydroquinoxalin-2-oneHCID 22912878—
SolventDimethylformamideHCID 6228—
SolventSodium chloride; waterHCID 57417360—
Product5-Fluoro-1-(2-methoxyethyl)-3,4-dihydro-1H-quinoxalin-2-oneHCID 23111097—

Reaction Steps

Sodium hydride (60%, 72 mg, 1.8 mmol) was added to a solution of 5-fluoro-3,4-dihydro-1H-quinoxalin-2-one from Example B (300 mg, 1.8 mmol) in DMF (6.0 ml) while cooling in an ice/water bath. The mixture was allowed to warm to room temperature and stirred for 0.5 h. The mixture was cooled in an ice/water bath and 2-bromoethyl methyl ether (170 μl, 1.8 mmol) and sodium iodide (140 mg, 0.9 mmol) were added. The mixture was allowed to warm to room temperature and stirred for 18 h. The mixture was diluted with brine and evaporated in vacuo. The residue was partitioned between EtOAc and brine and separated. The organic phase was dried and evaporated. The residue was purified by flash chromatography (eluant EtOAc:pet.ether 55:45) to give a pale yellow gum; yield 200 mg, 50%.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS08063038B2
Source datasetuspto-grants-2011_11
ORD IDord-8e266665f1d94f2bbdde020b8c1a4094
Source noteuspto-grants-2011_11