HRID561586

反应详情

EQUATION

反应方程式

HRID 561586 的结构方程式

PROCEDURE

实验过程

The title compound was prepared starting from 350 mg (1.97 mmol) of the compound from Example 8 and 470 mg (1.97 mmol) of the compound from Example 84A in analogy to the synthesis of the compound from Example 101. 191 mg (24% of theory) of the target compound were obtained.

WORKUP

后处理

  1. custom191 mg (24% of theory) of the target compound were obtained