HRID561592

反应详情

EQUATION

反应方程式

HRID 561592 的结构方程式

PROCEDURE

实验过程

The title compound was prepared starting from 217 mg (94% purity, 0.61 mmol) of the compound from Example 96 in analogy to the synthesis of the compound from Example 91. 212 mg (99% of theory) of the target compound were obtained as mixture of diastereomers.

WORKUP

后处理

  1. custom212 mg (99% of theory) of the target compound were obtained as mixture of diastereomers