HRID561640

反应详情

EQUATION

反应方程式

HRID 561640 的结构方程式

PROCEDURE

实验过程

The title compound was prepared starting from 32 mg (0.18 mmol) of the compound from Example 8A and 43 mg (0.18 mmol) of the compound from Example 144A in analogy to the synthesis of the compound from Example 186. 38 mg (53% of theory) of the target compound were obtained.

WORKUP

后处理

  1. custom38 mg (53% of theory) of the target compound were obtained