HRID561641

反应详情

EQUATION

反应方程式

HRID 561641 的结构方程式

PROCEDURE

实验过程

The title compound was prepared starting from 84 mg (0.48 mmol) of the compound from Example 8A and 100 mg (0.48 mmol) of the compound from Example 145A in analogy to the synthesis of the compound from Example 186. 38 mg (21% of theory) of the target compound were obtained.

WORKUP

后处理

  1. custom38 mg (21% of theory) of the target compound were obtained