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HRID561651

反应详情

EQUATION

反应方程式

HRID 561651 的结构方程式

REACTANTS

反应物

2
结构：CSCc1cccc2c(C(C)(c3ccc4c(c3)OC(F)(F)O4)C3CC3)c[nH]c12
HCID58392217

未命名化合物

结构：CC(c1ccc(Cl)cc1)(c1c[nH]c2c(CS(C)(=O)=O)cccc12)C1CC1
HCID58392388

未命名化合物

PRODUCTS

生成物

1
结构：CC(c1ccc2c(c1)OC(F)(F)O2)(c1c[nH]c2c(CS(C)(=O)=O)cccc12)C1CC1
HCID58392500

未命名化合物

PROCEDURE

实验过程

The title compound was prepared starting from 33 mg (0.08 mmol) of the compound from Example 190 in analogy to the synthesis of the compound from Example 209. 27 mg (76% of theory) of the target compound were obtained.

WORKUP

后处理

  1. custom27 mg (76% of theory) of the target compound were obtained