HRID561664

反应详情

EQUATION

反应方程式

HRID 561664 的结构方程式

PROCEDURE

实验过程

The title compound was prepared starting from 200 mg (1.02 mmol) of the compound from Example 11A and 206 mg (1.02 mmol) of the compound from Example 156A in analogy to the synthesis of the compound from Example 227. 247 mg (64% of theory) of the target compound were obtained.

WORKUP

后处理

  1. custom247 mg (64% of theory) of the target compound were obtained