HRID561666

反应详情

EQUATION

反应方程式

HRID 561666 的结构方程式

PROCEDURE

实验过程

The title compound was prepared starting from 500 mg (2.56 mmol) of the compound from Example 9A and 468 mg (2.56 mmol) of the compound from Example 153A in analogy to the synthesis of the compound from Example 233. 411 mg (44% of theory) of the target compound were obtained.

WORKUP

后处理

  1. custom411 mg (44% of theory) of the target compound were obtained