HRID561697

反应详情

EQUATION

反应方程式

HRID 561697 的结构方程式

PROCEDURE

实验过程

The title compound was prepared starting from 750 mg (4.23 mmol) of the compound from Example 8A and 961 mg (4.23 mmol) of the compound from Example 173A in analogy to the synthesis of the compound from Example 278. 276 mg (17% of theory) of the target compound were obtained.

WORKUP

后处理

  1. custom276 mg (17% of theory) of the target compound were obtained