Back
HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 575135Generated: October 30, 2026

Lithium Hydroxide → 9-Bromo-10-fluoro-3-formyl-2,5-diazatetracyclo[11.1.1.0[2,6].0[7,12]]pentadeca-3,5,7(12),8,10-pentaene-4-carboxylic acid

https://huagongshe.com/reaction/575135

Reaction equation

Participants

RoleNameHCIDCharge
ReactantLithium HydroxideHCID 3939—
ReactantMethyl 9-bromo-10-fluoro-3-formyl-2,5-diazatetracyclo[11.1.1.0[2,6].0[7,12]]pentadeca-3,5,7(12),8,10-pentaene-4-carboxylateHCID 86693159—
SolventMethanol--water (1/1)HCID 22242641—
Product9-Bromo-10-fluoro-3-formyl-2,5-diazatetracyclo[11.1.1.0[2,6].0[7,12]]pentadeca-3,5,7(12),8,10-pentaene-4-carboxylic acidHCID 8669316074.8%

Reaction Steps

Methyl 9-bromo-10-fluoro-3-formyl-2,5-diazatetracyclo[11.1.1.0[2,6].0[7,12]]pentadeca-3,5,7(12),8,10-pentaene-4-carboxylate (125 mg) was saponified with LiOH in H2O/MeOH to give 90 mg of 9-bromo-10-fluoro-3-formyl-2,5-diazatetracyclo[11.1.1.0[2,6].0[7,12]]pentadeca-3,5,7(12),8,10-pentaene-4-carboxylic acid.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS09034866B2
Source datasetuspto-grants-2015_05
ORD IDord-ee4796d266014e13891969d3ecf09527
Source noteuspto-grants-2015_05