Hydrogen Bromide → 4-Hydroxy-6-fluorophenanthridine
Reaction equation
C[O:2][C:3]1[C:16]2[C:7](=[C:8]3[C:13](=[C:14]([F:17])[N:15]=2)[CH:12]=[CH:11][CH:10]=[CH:9]3)[CH:6]=[CH:5][CH:4]=1.Br.C(=O)([O-])[O-].[Na+].[Na+]>>[OH:2][C:3]1[C:16]2[C:7](=[C:8]3[C:13](=[C:14]([F:17])[N:15]=2)[CH:12]=[CH:11][CH:10]=[CH:9]3)[CH:6]=[CH:5][CH:4]=1Participants
4
Procedure
A mixed solution comprising 115 mg of 4-methoxy-6-fluorophenanthridine and 5 ml of 48% hydrobromic acid was allowed to react at 116° C. for a period of 14 hr. After the completion of the reaction, the reacted solution was introduced into an aqueous solution of sodium carbonate and the product was extracted by ethyl acetate. After ethyl acetate was distilled away, the residue was purified by column chromatography to obtain 104.5 mg of 4-hydroxy-6-fluorophenanthridine on recrystallization from hexane (yield 96.9%).
Workup
- customto react at 116° C. for a period of 14 hr
- customAfter the completion of the reaction
- extractionthe product was extracted by ethyl acetate
- distillationAfter ethyl acetate was distilled away
- customthe residue was purified by column chromatography
Sources & evidence
- ORD record
- ord-242d72649d2648c380bcd1e144f7279b
- Source dataset
- uspto-grants-1999_07
- Patent number
- US05919928
Reaction notes
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