HRID582777

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID3283

Diethyl Ether

C4H10O

HCID7371

Benzenesulfonic acid

C6H6O3S

结构：COc1cccc(OC)c1-c1cc(C(=O)NC2(C(=O)O)C3CC4CC(C3)CC2C4)nn1-c1ccc(C(=O)N(C)CCCN(C)C)cc1C(C)C

HCID5311451

2-[[[5-(2,6-Dimethoxyphenyl)-1-[4-[[[3-(dimethylamino)propyl]methylamino]carbonyl]-2-(1-methylethyl)phenyl]-1H-pyrazol-3-yl]carbonyl]amino]tricyclo[3.3.1.13,7]decane-2-carboxylic acid

C39H51N5O6

PRODUCTS

生成物

结构：COc1cccc(OC)c1-c1cc(C(=O)NC2(C(=O)O)C3CC4CC(C3)CC2C4)nn1-c1ccc(C(=O)N(C)CCCN(C)C)cc1C(C)C.O=S(=O)(O)c1ccccc1

HCID86754283

未命名化合物

收率 9.8%

AUXILIARIES

试剂、催化剂与溶剂

溶剂HCID887

Methanol

CH4O

PROCEDURE

实验过程

A mixture of 0.5 g of the compound obtained in EXAMPLE 1' and 0.16 g of benzenesulphonic acid in 5 ml of MeOH is poured. into 75 ml of ether cooled to 5° C., and the precipitate formed is drained. 0.06 g of the expected product is obtained, m.p.=170° C. (dec.).

WORKUP

后处理

additionis poured
customthe precipitate formed

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-fa26715391c84d6d8b6ebccfad6dab24
来源数据集: uspto-grants-1999_07
DOI: 10.6084/m9.figshare.5104873.v1
专利: US05925661
来源说明: uspto-grants-1999_07

反应 SMILES

[CH3:1][O:2][C:3]1[CH:8]=[CH:7][CH:6]=[C:5]([O:9][CH3:10])[C:4]=1[C:11]1[N:15]([C:16]2[CH:21]=[CH:20][C:19]([C:22](=[O:31])[N:23]([CH3:30])[CH2:24][CH2:25][CH2:26][N:27]([CH3:29])[CH3:28])=[CH:18][C:17]=2[CH:32]([CH3:34])[CH3:33])[N:14]=[C:13]([C:35]([NH:37][C:38]2([C:48]([OH:50])=[O:49])[CH:45]3[CH2:46][CH:41]4[CH2:42][CH:43]([CH2:47][CH:39]2[CH2:40]4)[CH2:44]3)=[O:36])[CH:12]=1.[C:51]1([S:57]([OH:60])(=[O:59])=[O:58])[CH:56]=[CH:55][CH:54]=[CH:53][CH:52]=1.CCOCC>CO>[C:51]1([S:57]([OH:60])(=[O:59])=[O:58])[CH:56]=[CH:55][CH:54]=[CH:53][CH:52]=1.[CH3:10][O:9][C:5]1[CH:6]=[CH:7][CH:8]=[C:3]([O:2][CH3:1])[C:4]=1[C:11]1[N:15]([C:16]2[CH:21]=[CH:20][C:19]([C:22](=[O:31])[N:23]([CH3:30])[CH2:24][CH2:25][CH2:26][N:27]([CH3:28])[CH3:29])=[CH:18][C:17]=2[CH:32]([CH3:34])[CH3:33])[N:14]=[C:13]([C:35]([NH:37][C:38]2([C:48]([OH:50])=[O:49])[CH:39]3[CH2:40][CH:41]4[CH2:42][CH:43]([CH2:44][CH:45]2[CH2:46]4)[CH2:47]3)=[O:36])[CH:12]=1