Hydrogen Peroxide → 6-Fluoro-8-nitroquinolin-3-ol
Reaction equation
[F:1][C:2]1[CH:3]=[C:4]2[C:9](=[C:10]([N+:12]([O-:14])=[O:13])[CH:11]=1)[N:8]=[CH:7][CH:6]=[CH:5]2.[OH:15]O>C(O)(=O)C.O>[F:1][C:2]1[CH:3]=[C:4]2[C:9](=[C:10]([N+:12]([O-:14])=[O:13])[CH:11]=1)[N:8]=[CH:7][C:6]([OH:15])=[CH:5]2Participants
5
Reactant 2
Product 1
Reagents, catalysts & solvents 2
Conditions
- Temperature
- 70 °C
Procedure
A solution of 6-fluoro-8-nitro-quinoline (900 mg, 4.7 mmol) in acetic acid (10 ml) was treated at room temperature with hydrogen peroxide (30% in water (1.6 ml), then it was stirred at 70° C. for 5 hours. For the workup, the reaction mixture was cooled and poured into ice-water. The precipitate was filtered, washed with water, collected and dried. 6-Fluoro-8-nitro-quinolin-3-ol was obtained as a brown solid (285 mg, 29%); (calculated) C9H5FN2O3 [208.2]; (found) [M−H]−=207.
Workup
- temperatureFor the workup, the reaction mixture was cooled
- filtrationThe precipitate was filtered
- washwashed with water
- customcollected
- customdried
Sources & evidence
- ORD record
- ord-5859934e03294e56ae6ad93d35871dab
- Source dataset
- uspto-grants-2016_01
- Patent number
- US09242943B2
Reaction notes
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