HRID597415

反应详情

EQUATION

反应方程式

HRID 597415 的结构方程式

PROCEDURE

实验过程

Reacting 4-hydroxymethyl-3-methylisothiazole (3.0 g) with cysteamine hydrochloride (2.8 g) in 48% aqueous hydrobromic acid (50 ml) by the procedure of Example 29 (ii) gives 3-methyl-4-[(2-aminoethyl)thiomethyl]isothiazole hydrobromide. The base is obtained by basifying with aqueous potassium carbonate, extracting with chloroform, drying the extracts over magnesium sulphate and concentrating. Using the amine (5.0 g) as the starting material in the procedure of Example 47 (ii) yields the title compound.