Acetophenone → 1-Phenylethanol
Reaction equation
O(C(C)(C)C)[Na].[C:7]([C:10]1[CH:15]=[CH:14][CH:13]=[CH:12][CH:11]=1)(=[O:9])[CH3:8]>C(O)(C)C>[CH3:8][CH:7]([OH:9])[C:10]1[CH:15]=[CH:14][CH:13]=[CH:12][CH:11]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Conditions
- Temperature
- 30 °C
Procedure
Into a 100-mL stainless-steel autoclave was put 24.0 mg (0.03 mmol) of [CuCl((R,R)-SKEWPHOS) (PPh3)]n obtained in Example 27, triphenyl phosphine of the amount shown in Table 6 below, and 28.8 mg (0.30 mmol) of NaO-t-Bu, followed by replacing with nitrogen in the autoclave, and then 2.0 mL of isopropyl alcohol and 1.05 mL (9.0 mmol) of acetophenone were added. The reaction was carried out with stirring under a hydrogen pressure of 5 MPa at 30° C. for 16 to 17 hours to give 1-phenethyl alcohol which is a hydrogenated compound of acetophenone. The reaction mixture was analyzed by using GC. The results are shown in Table 6.
Sources & evidence
- ORD record
- ord-0fb5e6c50cb749a6887872802e3a3df6
- Source dataset
- uspto-grants-2011_03
- Patent number
- US07902110B2
Reaction notes
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